Therefore:
$$
\underset{m = 0^{64}}{L_2} \oplus \underset{m = 1^{32}0^{32}}{L_2} \equiv 1^{32}
$$
Therefore:
$$
c_1 = c'_0
$$
相隔天堑 却不觉遥远
Therefore:
$$
\underset{m = 0^{64}}{L_2} \oplus \underset{m = 1^{32}0^{32}}{L_2} \equiv 1^{32}
$$
Therefore:
$$
c_1 = c'_0
$$